http://image.so.com/v?ie=utf-8&q=如图所示%2C已知在三角形ABC中%2C角ACB等于90度%2CCD垂直AB%2C垂足为D%2C求证∠A%3D∠dcb&src=tab_se&fromurl=http%3A%2F%2Fiask.sina.com.cn%2Fb%2F17960045.html#ie=utf-8&q=%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E5%B7%B2%E7%9F%A5%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92ACB%E7%AD%89%E4%BA%8E90%E5%BA%A6%2CCD%E5%9E%82%E7%9B%B4AB%2C%E5%9E%82%E8%B6%B3%E4%B8%BAD%2C%E6%B1%82%E8%AF%81%E2%88%A0A%3D%E2%88%A0dcb&src=tab_se&fromurl=http%3A%2F%2Fiask.sina.com.cn%2Fb%2F17960045.html&lightboxindex=5&id=6029ec27ee618d1f6713894880897617&multiple=0&itemindex=0&dataindex=13
如图所示，已知在三角形ABC中，角ACB等于90度，CD垂直AB，垂足为D，求证∠A=∠dcb
亲，图呢？？
